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5v^2-5v-30=0
a = 5; b = -5; c = -30;
Δ = b2-4ac
Δ = -52-4·5·(-30)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-25}{2*5}=\frac{-20}{10} =-2 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+25}{2*5}=\frac{30}{10} =3 $
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